Physics › Particles › Conservation laws
Conservation laws
A proposed interaction is allowed only if the relevant quantum numbers are conserved. Charge, baryon number, the two lepton numbers and strangeness must all balance, and energy and momentum must be conserved as well. If any one of them fails, the interaction does not happen.
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Builds on Quarks and antiquarks and Stable and unstable nuclei.
IN THIS TOPIC
- Describe the quark character change in β− and β+ decay.
- Audit interactions against conservation of charge, baryon number, lepton number and strangeness.
- Recognise that energy and momentum are conserved in every interaction, and that either can forbid one.
- For Edexcel, interpret a particle-track photograph, reading the sign of a charge from the curl, the momentum from the radius and lost energy from a spiral.
COMMON MISCONCEPTION
In particle physics, anything can happen.
Beta decay as a change of flavour
Both beta decays are single-quark events. In β− a down quark becomes an up, d → u, with the W− carrying off the charge and turning into e− plus an electron antineutrino. In β+ an up becomes a down, u → d, via a W+ that gives a positron and an electron neutrino. State the quark change, name the W, and the mark scheme is satisfied.
The audit
Whether a proposed interaction is allowed comes down to a line-by-line audit. Charge must balance. So must baryon number. Lepton number must balance for the electron family and the muon family separately, which is where most candidates come unstuck. Strangeness must balance in strong interactions, though it may shift by 0 or ±1 in weak ones.
Work in columns, one quantum number at a time, totalling each side of the arrow. For any particle outside the familiar set, the necessary data will be provided in the question, so this is careful checking and nothing to recall. A single failed line means the interaction cannot occur, and no exception to these conservation laws has been observed.
WORKED EXAMPLE
An audit that fails, and the fix
A student writes neutron decay as n → p + e−, with no third product. Audit it.
Charge runs 0 → +1 − 1 = 0, which passes. Baryon number runs 1 → 1 + 0, which passes.
Lepton number runs 0 → 0 + 1. That fails. One failed line is enough, so the decay cannot happen as written.
The fix is an electron antineutrino, lepton number −1, giving n → p + e− + e and balancing every line. The audit rejected an equation and predicted a particle in the same stroke.
GUIDED PRACTICE
A neutrino interaction
Audit the interaction νμ + n → μ− + p: charge, baryon number, and both lepton numbers. Run all four lines.
Show the working
Charge runs 0 + 0 → −1 + 1 = 0. Baryon number runs 0 + 1 → 0 + 1. Muon lepton number runs 1 + 0 → 1 + 0. Electron lepton number is zero throughout.
All four pass, so no conservation law forbids the interaction; with enough incident energy for energy and momentum to balance as well, it happens. Detectors identify muon neutrinos in exactly this way.
The two laws that always apply
Beyond the quantum numbers, energy and momentum are conserved in every interaction, and either can forbid a process that the quantum numbers allow. The standard example follows. A free proton decaying by p → n + e+ + νe balances charge, baryon number and electron lepton number perfectly, and it never happens, because the products' rest energies, about 939.6 MeV plus 0.511 MeV, exceed the proton's 938.3 MeV. No energy is available to make up the difference, so the decay is forbidden. That is the explanation of the proton's stability left open two lessons ago. Inside a nucleus the energy balance is different, and bound protons can undergo β+ decay where free ones cannot.
Momentum forbids processes just as firmly, and the antimatter lesson has already shown it doing so. A lone photon in empty space cannot become an electron-positron pair however much energy it carries, because no arrangement of that pair balances energy and momentum at once, which is why pair production requires a nearby nucleus to take the recoil. Keep the two checks separate. Energy sets whether there is enough available, and momentum sets whether the products can be arranged so that it is conserved.
Reading particle tracks, an Edexcel skill
Edexcel is the one board that puts a detector photograph in front of you and asks what it shows, so read this section only if Edexcel is your specification. Nothing in it is new physics. It is the audit you have just learned, run on a picture instead of an equation.
A detector records a charged particle because the particle ionises whatever it flies through, and that trail of ions is made visible, as a string of bubbles in a bubble chamber or as a run of hits in a modern tracker. A neutral particle ionises nothing and so leaves no track at all. Treat the absence as evidence rather than a hole in the picture. A pair of tracks springing out of empty space, with a clear run behind them, says a neutral particle crossed that gap unseen, and it is drawn dashed because nobody saw it. A neutral kaon or a Λ0 appears in exactly this way, as a V with nothing leading into it.
A magnetic field across the chamber bends every charged track, and the magnetic fields unit sets that magnetic force against the centripetal one to get the radius, which it writes as r = mv/BQ and Edexcel writes as . They are one relation, since p = mv.
Two readings come straight off the photograph. Which way a track curls gives the sign of the charge, once the field direction and the direction of travel are known; without those, the curl still separates the charges, since opposite signs bend opposite ways in one field. How tightly a track curls gives the momentum, a wide gentle arc marking high momentum and a tight one low; the photograph is read in the plane perpendicular to the field, so strictly the radius measures the momentum component in that plane, and speed follows only once the particle is identified. A straight track is simply the wide end of that scale, too much momentum to bend measurably.
A track that spirals is the same rule applied twice. The particle is ionising as it goes, every ion it makes takes energy from it, so its momentum falls, and by r = p/(BQ) the radius falls with it until the curve winds itself in. So a spiral reads two things at once. This particle is losing energy, and the tight end is the late end. Direction of travel follows from it, which matters more than it looks, because reading the same picture backwards turns every charge in it upside down.
Now audit the vertex, where the conservation laws of this lesson meet the photograph. Charge is counted by curl, so two daughters curling opposite ways carry opposite signs, and if nothing led into the vertex those charges have to cancel exactly. Momentum is a vector sum, so the daughters' momenta, each read from a radius and pointed along its own track, must add to the parent's momentum along the invisible line, which is why the two arms of a V straddle that line instead of leaning to one side. Energy is the last check, the parent having to cover the daughters' rest energies with enough left over for the kinetic energy those momenta imply.
WORKED EXAMPLE
One V, read off the picture
Two tracks spring from a point with nothing leading into it. One curls clockwise on a tight arc and the other anticlockwise on an arc about three times wider, in a uniform field. State what can be deduced about the parent and the two daughters.
Nothing arrives at the vertex, so the parent was neutral: only a charged particle ionises, and only ionisation leaves a track. Its path is real but invisible, running back from the vertex along the direction in which the two daughters' momenta add up.
The daughters curl opposite ways, so they carry opposite signs, and since the parent's charge was zero their charges must cancel exactly rather than merely differ.
Radius is momentum. With one field and equal magnitudes of charge, r = p/(BQ) makes the wider track's momentum about three times the tighter one's.
Not one number came off a data sheet. The sign came from a direction of curl, the momentum from a radius, and the parent from a gap, which is what interpreting a track photograph involves.
INDEPENDENT PRACTICE
The track that tightens
A charged particle enters a bubble chamber and its track spirals inwards, tightening turn by turn. A classmate says the spiral shows the particle speeding up, since it is turning faster and faster. Correct them, and say which end of the spiral the particle reached last.
Show the working
Turning faster is not going faster. The radius is r = p/(BQ), so a tightening spiral is a falling momentum, and the particle is being slowed by ionising the liquid it crosses.
The tight end is therefore the late end, reached last. Getting that the right way round is what fixes the direction of travel, and the direction of travel is what fixes the sign of the charge, so one misread spiral takes the whole answer with it.
ASSESSMENT FOCUS
- The audit format is itself worth marks. One row per quantum number, totals on both sides, a verdict on each row. Show the table even when your answer is “not allowed”.
- Lepton numbers are audited per family. An interaction turning a muon neutrino into an electron fails, however neatly the grand total seems to add up.
- Strangeness carries a conditional rule, conserved in strong interactions and free to change by 0 or ±1 in weak ones. Say which interaction you are auditing before you apply it.
- Unfamiliar particle in the question? Its quantum numbers will be printed right there. Read them, and never guess from the symbol.
- When every ledger balances and the process still cannot occur, look to energy and compare rest energies from the data booklet. That is why a free proton does not decay. If the energy is available and the process still fails, check momentum, which is the lone photon's problem in pair production.
- Edexcel track questions are answered with four fixed sentences, so learn them. No track means the particle was neutral. Direction of curl gives the sign of the charge. Radius gives the momentum through r = p/(BQ). A tightening spiral means energy is being lost to the chamber, and the tight end came last.
- In a track question, settle the direction of travel before you name a single charge, because a photograph read backwards gives every sign the wrong way round. A spiral fixes it for you, and a vertex fixes it too: tracks that spring apart from a point were all made after it.
CHECK YOURSELF
A student proposes that a free proton decays: p → n + e+ + νe. Audit the conservation laws, then explain what actually forbids the decay. (Rest energies: p 938.3 MeV, n 939.6 MeV, e 0.511 MeV.)
Show a hint
Every quantum number balances. So check the one thing left.
Show the answer
Charge runs +1 → 0 + 1 + 0 ✓. Baryon number runs +1 → +1 ✓. Electron lepton number runs 0 → 0 − 1 + 1 = 0 ✓. Strangeness stays at 0 ✓. Every quantum number balances.
Energy does not. The products carry at least 939.6 + 0.511 = 940.1 MeV of rest energy, which is more than the proton's 938.3 MeV, and a free proton has no spare energy to make up the difference.
Energy conservation forbids the decay, and the proton stays the only stable free baryon. Inside a nucleus the binding-energy balance is different, and that difference is what permits β+ decay there.
Audit charge, baryon and lepton numbers, and strangeness.
Energy and momentum must be conserved as well.
WORKBOOK
Printable practice for this topic: original exam-style questions with room to work, and a fully worked answer book. Free to use; please do not redistribute or sell.
Or read them with their mark schemes on the conservation laws questions page.
CHECK YOUR PROGRESS
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- Describe the quark character change in β− and β+ decay.
- Audit interactions against conservation of charge, baryon number, lepton number and strangeness.
- Recognise that energy and momentum are conserved in every interaction, and that either can forbid one.
- For Edexcel, interpret a particle-track photograph, reading the sign of a charge from the curl, the momentum from the radius and lost energy from a spiral.
Open the full revision checklist to track your progress across the whole unit.